Studying with toad is just asking for it. I stare.
Toad: Eh tomorrow when will you be taking the mrt.
Me: Er 6.30?
Toad: EH I DOWAN WAKE UP SO EARLY. 6.35 can!
Me: DOWANNN.
Toad: Okay 6.35.
Me: NO.
Toad: In case you didn't realize, that wasn't a question.
Me: ER and you're going to stop me, how?
Toad: I'll be there earlier to keep you from boarding the train!
Me: ...
*five minutes later*
Toad: Walao if I take 6.30 train I have to wake up at 5.50 please!
Me: Er i'll have to wake up even earlier?
Toad: NO YOU DON'T. I BET YOU'LL WAKE UP AT 6.10 OR SOMETHING.
Me: And you know because...
Toad: I DO
*and in case anyone wondered what caused the five minutes break*
Bus: *stops at the stop*
Us: *totters to the door. Pause. Stares at closed door.*
Me: *presses doorbell*
Door: *doesn't move*
Toad: *moves towards door at the front*
Door: *opens*
The world just hates toad.
And herein I present to you
How To Get Full Marks for Maths Promos
Qn: Calculate the area of the sphere, radius x cm.
Ans: I cannot answer this question due to considerations of its practical application in the real world. As a sphere is three-dimensional and lacks any flat surface, it is difficult to get an accurate measure either the diameter or the radius. Even if one attempted to calculate this from the sphere's circumference, it is hard to obtain the real circumference due to the round nature of the sphere.
Hence I suggest that one submerges the sphere in a regular cylindrical container half-filled with water, and the change in height of the water level x the base area of the container would give the volume of the sphere.
In cases requiring calculations about the rate of change of the volume of the sphere, it is also much easier to measure the rate of change of the height of water and multiply by the base area of the container.
Once one obtains the volume of the sphere, he or she can divide by 4/3 pi and cube root it to find the radius, which would most likely be much more accurate than the value gotten through direct measurement. Of course, with the value of the volume in hand, the question remains of why one would need to find the radius anyway.
Oh good grief am I bored or what.